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In mathematics, especially in set theory, the terms, subset, superset and proper (or strict) subset or superset are used to describe the relation, called inclusion, of one set being contained inside another set. Informally, every element belonging to subset A also belongs to superset B, but there may be elements belonging to B that do not belong to A (see diagram to right).
Definitions A set A is considered to be a subset of a set B, if A is "contained" inside B. Every set is a subset of itself. In this example, B would then be considered a superset of A. More formally, If A and B are sets and every element of A is also an element of B, then: If A is a subset of B, but A is not equal to B, then A is also a proper (or strict) subset of B. This is written as A ⊂ B. In the same way, B ⊃ A means that B is a proper superset of A. If A is a proper subset of B, then there exists at least one element x of B which is not an element of A. For any set S, inclusion is a binary relation on the set of all subsets of S (the power set of S). Symbols An easy way to remember the difference in symbols is to note that ⊆ and ⊂ are analogous to ≤ and <. For example, if A is a subset of B (written as A ⊆ B), then the number of elements in A is less than or equal to the number of elements in B (written as |A| ≤ |B|). Likewise, for finite sets A and B, if A ⊂ B then |A| < |B|. Many authors do not follow the above conventions, but use ⊂ to mean simply subset (rather than proper subset). There is an unambiguous symbol, (or in Unicode), for proper subset. Some authors use both unambiguous symbols, ⊆ for subset and for proper subset, and dispense with ⊂ altogether. The corresponding remarks apply for supersets as well. Examples Properties PROPOSITION 1: The empty set is a subset of every set. Proof: Given any set A, we wish to prove that ø is a subset of A. This involves showing that all elements of ø are elements of A. But there are no elements of ø. For the experienced mathematician, the inference " ø has no elements, so all elements of ø are elements of A" is immediate, but it may be more troublesome for the beginner. Since ø has no members at all, how can "they" be members of anything else? It may help to think of it the other way around. In order to prove that ø was not a subset of A, we would have to find an element of ø which was not also an element of A. Since there are no elements of ø, this is impossible and hence ø is indeed a subset of A. The following proposition says that inclusion is a partial order. PROPOSITION 2: If A, B and C are sets then the following hold: reflexivity:
antisymmetry:
transitivity:
The following proposition says that for any set S the power set of S ordered by inclusion is a bounded lattice, and hence together with the distributive and complement laws for unions and intersections (see The fundamental laws of set algebra), show that it is a Boolean algebra. PROPOSITION 3: If A, B and C are subsets of a set S then the following hold: existence of a least element and a greatest element:
existence of joins:
existence of meets:
The following proposition says that, the statement "A ⊆ B ", is equivalent to various other statements involving unions, intersections and complements. PROPOSITION 4: For any two sets A and B, the following are equivalent:
The above proposition shows that the relation of set inclusion can be characterized by either of the set operations of union or intersection, which means that the notion of set inclusion is axiomatically superfluous. PROPOSITION 5: If the number of elements of the set A is n, then the number of all subsets of A is equal to 2^n The proof of this is an exercise in induction. Other properties of inclusion The usual order on the ordinal numbers is given by inclusion. For the power set of a set S, the inclusion partial order is (up to an order-isomorphism) the Cartesian product of |S| (the cardinality of S) copies of the partial order on , for which 0 < 1. | ||||||||
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