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    In Rome, merchants used Roman numerals to perform basic arithmetic operations. In modern education, the Roman arithmetic used by the Romans is seldom taught. The preferred method is to convert the Roman numeral into an Hindu-Arabic numeral and solve the equation using a modern positional notation system. While this is more practical, it is not really learning how to add, subtract, multiply and divide Roman numerals, it is only making the student practice converting from Roman to Arabic and back again. Except for historical purposes, none of this is particularly useful to the grade student unless it is used to demonstrate the existence of different numeral systems and their impact on arithmetic and to do that, the student needs to learn how to perform arithmetic operations in the native numeral system.
    The two most basic operations of arithmetic are addition and subtraction. Multiplication is specialized form of addition where you quickly add identical numbers and division is a specialized form of subtraction where you quickly remove identical numbers.

    The use of subtractive notation with Roman numerals increased the complexity of performing basic arithmetic operations without conveying the benefits of a full positional notation system. In the algorithms that follow, the first step is to remove the subtractive notation from the numerals before any arithmetic operations. The subtractive notation is then reapplied to the solution as the end of the operation.

    The Roman abacus was a hand-held tool for assisting in the computations using Roman numerals.


        Roman arithmetic
            Basic operations
                    Example
                    Discussion
                    Example
                    Discussion
            Compound operations
                Multiplication
                    Example
                    Discussion
                Division
                    Example
                    Discussion

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    Basic operations

    All arithmetic operations can be broken down to combinations of addition and subtraction.

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    Example
    CXVI + XXIV = ?



    Solution:
    CXVI + XXIV = CXL

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    Discussion

    Step 1 decodes the positional data in the terms and replaces it with primitive counts. Now represented as a pure counting system, the concatenation of the terms in Step 2 gives the correct solution to the problem: CXVIXXIIII represents the same number as CXL — both terms convert to 140 in Arabic numerals. Steps 3 & 4 now reduce the result to the simplest expression possible and Step 5 reintroduces subtractive notation transforming the result back into a positional number.

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    Example
    CXVI − XXIV = ?



    Solution:
    CXVI − XXIV = XCII

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    Discussion

    Step 1 decodes the positional data in the terms and replaces it with primitive counts. In Step 2, like numerals are eliminated from both terms: a count of X and a count of I are each removed from each term, leaving a simplified problem of CV − XIII. Step 3 then expands the first term until it contains a common numeral (X) to the highest numeral in the second term. Step 2 is then repeated, followed by Step 3 until all of the numerals in the second term have been eliminated. Once all of the numerals of have been eliminated, the remaining numerals in the first term represent the solution as a primitive count. Step 5 reintroduces subtractive notation transforming the result back into a positional number.

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    Compound operations

    Having defined the process where by addition and subtraction operations can be performed using only Roman numerals, the other two traditional operations of arithmetic, multiplication and division, can now be accomplished.

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    Multiplication

    multiplicand × multiplier = product

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    Example
    XIV × VII = ?



    Solution:
    XIV × VII = XCVIII

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    Discussion

    Step 1 decodes the positional data in the terms and replaces it with primitive counts. Step 2 adds the multiplicand to product. Since subtractive notation has been removed in Step 1 and is later encoded in Step 5, there is no longer a requirement to perform the same processes when performing addition or subtraction within the multiplication operation. Step 3 reduces the number if iterations remaining for the addition operation in Step 2 by decreasing the value of the multiplier. Step 5 reintroduces subtractive notation transforming the result back into a positional number.

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    Division

    dividend / divisor = quotient

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    Example
    CXXI / V = ?



    Solution:
    CXXI / V = XXIV remainder I

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    Discussion

    Step 1 decodes the positional data in the terms and replaces it with primitive counts. Step 2 subtracts the divisor from the dividend. Since subtractive notation has been removed in Step 1 and is later encoded in Step 5, there is no longer a requirement to perform the same processes when performing addition or subtraction within the division operation. Step 3 increases the counter used for the quotient if remaining count of the dividend is greater than the divisor. Step 5 reintroduces subtractive notation transforming the result back into a positional number.




     
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    This article is licensed under the GNU Free Documentation License [copyleft]. It uses material from the Wikipedia article "Roman arithmetic". link